Mathematically:
f(x) = 0 a < x < b;
f(x) = (x - b) x > b;
f(x) = (x + a) x < a .
The transfer function (from Johnson 'Analog Computer Techniques', 1956, page 115) looks like this:
Here's my realisation of the circuit (sans vacuum tubes):
f(x) = 0 a < x < b;
f(x) = (x - b) x > b;
f(x) = (x + a) x < a .
The transfer function (from Johnson 'Analog Computer Techniques', 1956, page 115) looks like this:
Here's my realisation of the circuit (sans vacuum tubes):
The final thing has two separate channels:
No comments:
Post a Comment